- To find missing numbers in an array first we need to make sure that array is sorted.
- After sorting we need to check that array each element with next element then we can find the difference.
- if Array is not sorted :To sort array use Arrays.sort(array);
- If difference is 1 then no need to do any thing because numbers are in order.
- If difference is not equal to 1 then we need to print all those numbers or pick those numbers and place it in one array.
- this would be the logic to find missing numbers in an array
- Here there may be a chance of array not starts with 1 then we need to check first itself whether array starts with 1 or not if not we need to print 1 to starting element of array.
- for example int a[]={4,5,6,8}; then we need to print 1 2 3 7.
Lets see a java example program to find missing numbers in an array.
Lets see a java example program to find missing numbers in an array.
- package arraysInterviewQuestions;
- public class PrintMissingNumbers {
- private static void findMissingNumber(int[] number){
- // take max length as last number in array
- int k[] = new int[number[number.length-1]];
- int m=0;
- if(number[0]!=1){
- for (int x = 1; x < number[0]; x++) {
- k[m] = x;
- m++;
- }
- }
- for (int i = 0; i < number.length -1; i++) {
- int j = i+1;
- int difference = number[j] - number[i] ;
- if(difference != 1 ){
- for (int x = 1; x < difference; x++) {
- k[m] = number[i] + x;
- m++;
- }
- }
- }
- System.out.println("missing numbers in array ::");
- for (int l = 0; l < m ; l++) {
- System.out.println( k[l]+" ");
- }
- }
- public static void main(String[] args) {
- int a[]= {2,4,6,9,10,20};
- //if Array is not sorted :To sort array use Arrays.sort(a);
- findMissingNumber(a);
- }
- }
- Change the array in main method and practice try to find missing elements in an array that contains 1 to 100 numbers.
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