Find top two maximum numbers in a array java

• Hi Friends today we will discuss about how to find top two maximum numbers in an array using java program.
• For this we have written separate function to perform logic
• findTwoMaxNumbers method takes integer  array as an argument
• Initially take two variables to find top to numbers and assign to zero.
• By using for each loop iterating array and compare current value with these values
• If our value is less than current array value then assign current value to max1 
• And assign maxone to maxtwo because maxtwo should be second highest.
• After completion of all iterations maxone will have top value and maxtwo will have second maximum value.
• Print first maximum and second maximum values.
• So from main method create array and pass to findTwoMaxNumbers(int [] ar).

Program #1: Java interview programs to practice: find top two maximum numbers in an array without recursion 

package arraysInterviewPrograms.java;

public class FindTopTwo {

public void findTwoMaxNumbers(int[] array){

       

 int maxOne = 0;

 int maxTwo = 0;

for(int i:array){

    if(maxOne < i){

           maxTwo = maxOne;

           maxOne =i;

     } else if(maxTwo < i){

                maxTwo = i;

     }

}

        

  System.out.println("First Maximum Number: "+maxOne);

  System.out.println("Second Maximum Number: "+maxTwo);

}

     

public static void main(String a[]){

        int num[] = {4,23,67,1,76,1,98,13};

        FindTopTwo obj = new FindTopTwo();

        obj.findTwoMaxNumbers(num);

        obj.findTwoMaxNumbers(new int[]{4,5,6,90,1});

}

}

Output:

First Maximum Number: 98

Second Maximum Number: 76

First Maximum Number: 90

Second Maximum Number: 6